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#include
#include
#include
using namespace std;
double calculateCharges( double hour );
int main()
{
double hour; // number of hours for current car
double currentCharge; // parking charge for current car
double totalCharges = 0.0; // total charges
double totalHours = 0.0; // total number of hours
bool first = true; // used for printing table headers
cout << fixed; // set floating-point number format
cout << "Enter the hours parked for 3 cars: ";
// loop 3 times for 3 cars
for ( int i = 1; i <= 3; i++ )
{
cin >> hour;
totalHours += hour; // add current hours to total hours
// if first time through loop, display headers
if ( first )
{
cout << setw( 5 ) << "Car" << setw( 15 ) << "Hours"
<< setw( 15 ) << "Charge\n";
first = false; // prevent from printing again
} // end if
// calculate current car's parking charge
currentCharge = calculateCharges( hour );
totalCharges += currentCharge; // update total charges
// display row data for current car
cout << setw( 3 ) << i << setw( 17 ) << setprecision( 1 ) << hour
<< setw( 14 ) << setprecision( 2 ) << currentCharge << "\n";
} // end for
// display row data for totals
cout << setw( 7 ) << "TOTAL" << setw( 13 ) << setprecision( 1 )
<< totalHours << setw( 14 ) << setprecision( 2 )
<< totalCharges << endl;
} // end main
double calculateCharges( double hour )
{
//算到底有幾小時
//24小時直接跳10
if(hour >= 24)
{
return 10;
}
//未達3小時
if(hour<=3)
{
return 2;
}
else
{
//自己寫的判斷方法(不使用數學函式庫)
//原理:強制轉換成int 減掉原本的double有不等於0就無條件進入
double temp = (hour-3); //算剩餘 (扣掉3小時的)
int sub_num = ((int)hour-3); //強制取整數
//算有幾個剩餘
if(temp-sub_num!=0) //相減判斷是否為0
{
return 2+(sub_num+1)*0.5; //加1 因為有餘數
}
else
{
return 2+sub_num*0.5;
}
}
}
#include
using namespace std;
int integerPower( int , int );
int main()
{
int exp; // integer exponent
int base; // integer base
cout << "Enter base and exponent: ";
cin >> base >> exp;
cout << base << " to the power " << exp << " is: "
<< integerPower( base, exp ) << endl;
} // end main
int integerPower( int base, int exp )
{
int temp=1;
if(exp<0)
{
exp*=-1;
}
for(int i =1;i<=exp;i++)
{
temp*=base;
}
return temp;
}
//不使用函式解法(因為main不能寫所以假如非直角會傳回0)
#include
#include
#include
using namespace std;
double hypotenuse( double side1, double side2);
int main()
{
double side1; // value for first side
double side2; // value for second side
cout << fixed; // set floating-point number format
// loop 3 times
for ( int i = 1; i <= 3; i++ )
{
cout << "\nEnter 2 sides of right triangle: ";
cin >> side1 >> side2;
// calculate and display hypotenuse value
cout << "Hypotenuse: " << setprecision( 1 )
<< hypotenuse( side1, side2 ) << endl;
} // end for
} // end main
double hypotenuse( double side1, double side2 )
{
double num1=1;
double num2=1;
for(int i =1;i<=2;i++)
{
num1 *=side1;
}
for(int i= 1;i<=2;i++)
{
num2 *=side2;
}
int c =num1+num2;
//算平方
for(int i=1;;i++)
{
int temp ;
temp = i;
if(temp*temp==c)
{
return temp;
}
if(i>c)
{
break;
}
}
// return sqrt(c);
}
//使用函式解法(無限制) Ps 兩個FOR多寫了 算了..
#include
#include
#include
using namespace std;
double hypotenuse( double side1, double side2);
int main()
{
double side1; // value for first side
double side2; // value for second side
cout << fixed; // set floating-point number format
// loop 3 times
for ( int i = 1; i <= 3; i++ )
{
cout << "\nEnter 2 sides of right triangle: ";
cin >> side1 >> side2;
// calculate and display hypotenuse value
cout << "Hypotenuse: " << setprecision( 1 )
<< hypotenuse( side1, side2 ) << endl;
} // end for
} // end main
double hypotenuse( double side1, double side2 )
{
double num1=1;
double num2=1;
for(int i =1;i<=2;i++)
{
num1 *=side1;
}
for(int i= 1;i<=2;i++)
{
num2 *=side2;
}
int c =num1+num2;
return sqrt(c);
}
4.
#include
#include
using namespace std;
int seconds( int, int, int );
int main()
{
unsigned hours; // current time's hours
unsigned minutes; // current time's minutes
unsigned secs; // current time's seconds
double first; // first time, in seconds
double second; // second time, in seconds
double difference; // difference between two times, in seconds
cout << "Enter the first time as three integers: ";
cin >> hours >> minutes >> secs;
first = seconds( hours, minutes, secs ); // calculate first time
cout << "Enter the second time as three integers: ";
cin >> hours >> minutes >> secs;
second = seconds( hours, minutes, secs ); // calculate second time
difference = fabs( first - second ); // calculate difference
// display difference
cout << "The difference between the times is "
<< difference << " seconds" << endl;
} // end main
int seconds( int hours, int minutes, int secs )
{
//static int temp;
int temp=hours*60*60+minutes*60+secs;
// int now=hours*60*60+minutes*60+secs;
return temp;
}
#include
using namespace std;
int isPerfect( int j ); // function prototype
void printSum( int value );
int main()
{
cout << "Perfect integers between 1 and 1000:" << endl;
// loop from 2 to 1000
for ( int j = 2; j <= 1000; j++ )
{
// if current integer is perfect
if ( isPerfect( j ) )
printSum( j ); // print it as sum of factors
} // end for
cout << endl;
} // end main
// printSum displays value followed by factors in summation form
void printSum( int value )
{
cout << value << " = 1";
// loop through possible factor values
for ( int i = 2; i <= value / 2; i++ )
{
// if i is factor
if ( value % i == 0 )
cout << " + " << i; // display as part of sum
} // end for
cout << endl;
} // end function printSum
//===================
int isPerfect( int j )
{
//這題不是我寫的 哈哈
int sum=0;
for(int i =1;i<j;i++)
{
if(j%i==0)
{
sum+=i;
}
}
if(sum==j)
return j;
else
return 0;
}
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